Find the derivative of the function. r(x) = (e^4x(squared)^6
Don't take this as fact. You should double check me. Here I go
\[6(e^{4x^2})^5(e^{4x^2})8x=48x(e^{4x^2})^6\]
thats what i got instead i had it squared by 5 not 6
I brought the power down then took the derivative of the inside, of which I had do the chain rule again.
I combined the ^5 and ^1 with the same base to get ^6. But this is the first time I've done this exact type of problem. You very well could be right.
oh you were right. thanks
yup
can you help me with one more question, similiar to this?
sure
\[e ^{2x^2-7x+2/x}\]
thats a tough one check me on this first. The derivative of 1/x is ln(x) right?
i think its this f ' (x) = -1 x ^ -2
You're right integral of 1/x is ln(x) and derivative of ln(x) is 1/x. Ok. Think you have to bring x to the top so x^-1 then use the product rule. I'll try it
is everything over x or just the 2
just 2
I was assuming everything was over x. This makes it simpler. You should still make it 2x^-1, but we don't have to use the product rule anymore
\[e^{2x^2-7x+2/x}(4x-7-2/x^2)\]
so everything is over x?
No, I thought the original problem was over x, but you said it was only the 2. So my answer above the 2 is only over x^2
oh ok, hm i guess i was wrong because it was incorrect for my hwk.
im not sure how to do this type of problem
\[e^{(\frac{ 2x^2-7x+2 }{ x })}\]Is that the problem
no its labeled like it is a few convos up. when u gave me the answer
Hmm. I wouldn't do anything different with my answer a few posts above. You should get a second opinion on this one I guess.
hm ok. this is a tough one.
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