Mathematics
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OpenStudy (anonymous):
Can anyone help me with solving this integral?
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OpenStudy (anonymous):
\[\int\limits_{2}^{5} (4-2x)dx\]
OpenStudy (amistre64):
which part is giving you night terrors?
OpenStudy (anonymous):
lol the 2nd one!
OpenStudy (amistre64):
what is the integration rule for x^n ?
OpenStudy (anonymous):
\[\int\limits_{2}^{5} 4.dx - 2\int\limits_{2}^{5}x.dx\]
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OpenStudy (amistre64):
or you can think of it in terms of derivatives; what is the derivative rule for x^n ?
OpenStudy (anonymous):
nx^n-1
OpenStudy (amistre64):
good, now how would you undo that? which is all an integration is ... undoing a derivative
OpenStudy (anonymous):
thats wht i am having trouble with!
OpenStudy (amistre64):
divide by n and add 1 back to the exponent
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OpenStudy (amistre64):
\[x=x^1\]right?
OpenStudy (anonymous):
x^1
OpenStudy (anonymous):
yea
OpenStudy (amistre64):
\[x^1=x^{2-1}\]so n=2 in this case
OpenStudy (anonymous):
ohh yea right!
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OpenStudy (amistre64):
so, does x^2 derive down to 2x?
OpenStudy (anonymous):
yea it will be 2x^2-1
OpenStudy (anonymous):
but we need x!
OpenStudy (amistre64):
but we already have a 2x
OpenStudy (amistre64):
you dont HAVE to pull out the constant. In this case it acutally helps out
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OpenStudy (anonymous):
2x/2
OpenStudy (amistre64):
\[\frac d{dx}x^2=2x\]
\[\int 2x~dx=x^2\]
OpenStudy (anonymous):
ohh gotch yea so, its gona be like (5-2)^2
OpenStudy (amistre64):
\[\int\limits_{2}^{5} 4.dx - \int\limits_{2}^{5}2x.dx\]
\[4x(5,2) - x^2(5,2)\]
\[[4(5)-4(2)] - [(5)^2-(2)^2]\]
OpenStudy (anonymous):
so i was doing just 1 term of x
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OpenStudy (amistre64):
you were mixing up the subtraction and the function into an ungodly abomination :)
OpenStudy (anonymous):
yea right, i got it now! Thank you very much.. :)
OpenStudy (amistre64):
\[\int_{a}^{b} f(x)~dx=F(b)-F(a)~NOT~F(b-a)\]
OpenStudy (anonymous):
-9
OpenStudy (amistre64):
20-8-(25-4)
20-8-25+4
24 - 33 = -9 yes
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OpenStudy (anonymous):
yayy.. thanks again!