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Mathematics 17 Online
OpenStudy (anonymous):

Can anyone help me with solving this integral?

OpenStudy (anonymous):

\[\int\limits_{2}^{5} (4-2x)dx\]

OpenStudy (amistre64):

which part is giving you night terrors?

OpenStudy (anonymous):

lol the 2nd one!

OpenStudy (amistre64):

what is the integration rule for x^n ?

OpenStudy (anonymous):

\[\int\limits_{2}^{5} 4.dx - 2\int\limits_{2}^{5}x.dx\]

OpenStudy (amistre64):

or you can think of it in terms of derivatives; what is the derivative rule for x^n ?

OpenStudy (anonymous):

nx^n-1

OpenStudy (amistre64):

good, now how would you undo that? which is all an integration is ... undoing a derivative

OpenStudy (anonymous):

thats wht i am having trouble with!

OpenStudy (amistre64):

divide by n and add 1 back to the exponent

OpenStudy (amistre64):

\[x=x^1\]right?

OpenStudy (anonymous):

x^1

OpenStudy (anonymous):

yea

OpenStudy (amistre64):

\[x^1=x^{2-1}\]so n=2 in this case

OpenStudy (anonymous):

ohh yea right!

OpenStudy (amistre64):

so, does x^2 derive down to 2x?

OpenStudy (anonymous):

yea it will be 2x^2-1

OpenStudy (anonymous):

but we need x!

OpenStudy (amistre64):

but we already have a 2x

OpenStudy (amistre64):

you dont HAVE to pull out the constant. In this case it acutally helps out

OpenStudy (anonymous):

2x/2

OpenStudy (amistre64):

\[\frac d{dx}x^2=2x\] \[\int 2x~dx=x^2\]

OpenStudy (anonymous):

ohh gotch yea so, its gona be like (5-2)^2

OpenStudy (amistre64):

\[\int\limits_{2}^{5} 4.dx - \int\limits_{2}^{5}2x.dx\] \[4x(5,2) - x^2(5,2)\] \[[4(5)-4(2)] - [(5)^2-(2)^2]\]

OpenStudy (anonymous):

so i was doing just 1 term of x

OpenStudy (amistre64):

you were mixing up the subtraction and the function into an ungodly abomination :)

OpenStudy (anonymous):

yea right, i got it now! Thank you very much.. :)

OpenStudy (amistre64):

\[\int_{a}^{b} f(x)~dx=F(b)-F(a)~NOT~F(b-a)\]

OpenStudy (anonymous):

-9

OpenStudy (amistre64):

20-8-(25-4) 20-8-25+4 24 - 33 = -9 yes

OpenStudy (anonymous):

yayy.. thanks again!

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