1+1/x / 1/x - x , x is not equall to zero please!
\[\frac{1+\frac{1}{x}}{\frac{1}{x}-x}\] Is that right? what happens when you multiply the whole thing by X/X?
yes thats exactly wht it looks like!
how do i solve it
There is no equals sign. The best you can do is simplify it... unless is it equal to something?
ohk so its not equivalent to anything ?
They would have to have made the thing =0 or something. You can simplify it... which is what I am assuming that they want you to do.
ok thank you (: what is its 1/3+1/3x / 1/x + 1/3 ? what should i do?
It's equivalent to its simplified form, tatyana, but there's no need to introduce an equals sign if it didn't originally come with one.
are you explaining the first equation or second?
Are there 2 equations?
how do i solve 1/3+1/3x / 1/x + 1/3
Ok, try to multiply by a fancy form if 1 that will get rid of all the fractions. Probably the lowest common denom. of all the fractions divided by itself. For example \[\frac{1+\frac{1}{3x}}{1+\frac{1}{5x}}\to \] \[\frac{1+\frac{1}{3x}}{1+\frac{1}{5x}}\frac{15x}{15x}\to \] \[\frac{15x+\frac{15x}{3x}}{15x+\frac{15x}{5x}}\to \] \[\frac{15x+\frac{5}{1}}{15x+\frac{3}{1}}\to \]
ok imma try!
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