Question

Compute the Derivative, if it exists: d/dx arcsin(x+1)^1/2

Answer 1

www.themathpage.com/acalc/inverse-trig.htm

tutorial.math.lamar.edu/Classes/CalcI/DiffInvTrigFcns.aspx

Answer 2

im still getting a weird answer

Answer 3

i get 1/(2-x)^(1/2)

Answer 4

when the answer is 1/2((-x)^1/2)((1+x)^(1/2))

Answer 5

\[1\div(2\sqrt{-x}\times \sqrt{1+x}\])

Answer 6

That's almost what I'm getting.

I used chain rule to get \[\large \frac{(1/2)(x+1)^{-1/2}}{1-(x+1)}\]

Then simplified to get I used chain rule to get \[\large (-2x(x+1)^{1/2})^{-1}\]

I might be missing something, though..

Answer 7

and i use \[1\div \sqrt{1-(\sqrt{x+1){}}^2}\]

Answer 8

you just plug it in like that, right?

Answer 9

don't forget the chain rule. you still have the derivative of \[\large (x+1)^{1/2}\] to account for in the final answer.

Answer 10

ohh