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Mathematics 15 Online
OpenStudy (anonymous):

I have a question: So, Determine if y = -2x3 + 3x2 + 36x - 7 is concave up, concave down, or neither concave up nor concave down on the interval (0; 2). Justify your answer. So I tried figuring this out and the answer I got was wrong. The correct answer somehow is "neither." My question is, WHY?! It makes no sense when I am doing it. Thank you!

OpenStudy (anonymous):

Dammit! I'm sorry, that is supposed to be x^3 and x^2 for the function. I apologize for my repetitive mistakes.

OpenStudy (anonymous):

it is this \[f(x)=-2x^3 + 3x^2 + 36x - 7 \]?

OpenStudy (anonymous):

yes it is!

OpenStudy (anonymous):

take the derivative twice what do you get?

OpenStudy (anonymous):

Hold on. Let me do this right.

OpenStudy (anonymous):

Okay I got -12x+6

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

yes that is it

OpenStudy (anonymous):

so if the second derivative is positive, function is concave up

OpenStudy (anonymous):

\[-12x+6>0\iff x<\frac{1}{2}\]

OpenStudy (anonymous):

Right, I got that.

OpenStudy (anonymous):

since it changes concavity at \(\frac{1}{2}\) it is not concave up on the entire interval \((0,2)\) not is it concave down on that entire interval. it changes concavity in that interval

OpenStudy (anonymous):

*nor

OpenStudy (anonymous):

Oh! Okay I think I got it. So just on that interval because it is from (0,2), it isn't concave up for the entire thing, correct? It basically gets cut off?

OpenStudy (anonymous):

Wouldn't it make it an inflection point though?

OpenStudy (anonymous):

yes it is a weird question i think

OpenStudy (anonymous):

Because if it changes, I would think that...?

OpenStudy (anonymous):

seems like they should just ask "where is it concave up and concave down?" but whatever

OpenStudy (anonymous):

I see. I think I understand it now. Thank you! This has been bothering me all day!

OpenStudy (anonymous):

yw

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