in a 1 litre vessel at 1000k are introduced 0.1 mole each of NO and Br2 and 0.01 mole of NOBr
2NO(g)+Br2(g)=2NOBr(g)
Kc=1.32*10^-2
determine the direction of the net reaction and calculate the partial pressure of NOBr in the vessel at equilibrium?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
@UnkleRhaukus @timo86m @ghazi
OpenStudy (anonymous):
hlp me out
OpenStudy (ghazi):
\[K _{p}=\frac{ P _{NoBr} }{ [P _{NO}]*[P _{Br2}] }\]
OpenStudy (ghazi):
and use Kp and Kc relation before this
OpenStudy (anonymous):
can u elaborate it
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
bt by this i will nt gt the answer.
OpenStudy (anonymous):
hey plz hlp me out
OpenStudy (anonymous):
plz hlp me out
OpenStudy (anonymous):
@saifoo.khan
OpenStudy (ghazi):
\[Kp=Kc*(RT)^{\Delta n}\]
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (ghazi):
now to find Kc you have been provided with everything
OpenStudy (anonymous):
Kc is given
OpenStudy (anonymous):
@DLS plz hlp me out
OpenStudy (anonymous):
@DLS can u hlp me out
OpenStudy (anonymous):
@lalaly
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
hlp me out.
OpenStudy (unklerhaukus):
i can not do these
OpenStudy (anonymous):
i know
OpenStudy (anonymous):
Find out the reaction quotient
OpenStudy (anonymous):
can u ? do
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
i dunno much more
OpenStudy (anonymous):
reaction quotient? i'm nt getting wati t mean
OpenStudy (anonymous):
(NOBr)^2 / (NO)^2 * (Br2)
OpenStudy (anonymous):
if its greater than kc, move backward, less than means forward
OpenStudy (anonymous):
oh i knew after this
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
pressure i dunno how to do
OpenStudy (anonymous):
can u eloborate it
OpenStudy (anonymous):
i dont know the pressure part
OpenStudy (anonymous):
hey plz hlp me out
OpenStudy (anonymous):
@saifoo.khan
Still Need Help?
Join the QuestionCove community and study together with friends!