I have the points (5,1) and (-3, 4) I have to put them in Slope Intercept, Point-Slope, and Standard form. I got Point-Slope. ( y - 1 = 3/8(x - 5) but I can't figure out the other two for the life of me! Anyone?

Question

anonymous · Answer

Point slope form is: $$y-y_{1}=m(x-x_{1})$$
Standard form is: $$Ax+By=C$$
Slope intercept form is: $$y=mx+b$$

anonymous · Answer

I know, I tried to work them out but the 3/8 is throwing me off. I've been working on this for over two hours now. :/ I used Khanacademy but his problems all came out even, which this won't and I'm scared to veer too far away from what I know that I'll mess it up.

anonymous · Answer

i need help can u help me

anonymous · Answer

Depends on what you need help with?

anonymous · Answer

Shouldn't your slope be negative?

anonymous · Answer

I get y-1=-3/8(x-5)

anonymous · Answer

It might be wrong? That was just the slope I came up with, both ways.

anonymous · Answer

To find the slope intercept form multiply -3/8 through (x-5)

-3/8(x) is easy to figure out what -3/8(5) is, put the 5 in a fraction form then multiply straight across.

$$(\frac{ -3 }{ 8 })(\frac{ 5 }{ 1 })=?$$

anonymous · Answer

You should get -3/8x-(-15/8) or -3/8x+15/8

now add the one from the left side to the right side

1+15/8 

find a common denominator first then add

8/8+15/8= 23/8

y=-3/8x +23/8 slope intercept form

to get standard form just  add 3/8x to the left side

3/8x +y = 23/8

anonymous · Answer

Thank you soo much!

anonymous · Answer

But wait, if you add 3/8x to one side don't you have to do it to the other as well?

anonymous · Answer

It seems like you can just leave it 3/8x + y = 23/8

anonymous · Answer

adding 3/8x to the left will cancel it out on the right

anonymous · Answer

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