Question

What is the derivative of y = 1/ x+radx

Answer 1

its this \(\frac{1}{x+\sqrt x}\)
right ?

Answer 2

if yes then , use quotient rule.....

Answer 3

y' = -1/(x+radx)^2 * (1+1/2radx)

Answer 4

yes, even thats correct..

Answer 5

\[y'=(\frac{ 1 }{ (x+\sqrt{x})^2 })(1+\frac{ 1 }{ 2\sqrt{x} })\] Would yo need to simplify any further?

Answer 6

Or, could you?

Answer 7

no, simplifying further would not help...
all you can do is
\(y'=(\frac{ 1 }{ (x+\sqrt{x})^2 })(\frac{ 1+2\sqrt x }{ 2\sqrt{x} })\)
which is not much simplified

Answer 8

Alright, thank you very much!

Answer 9

welcome :)