When a generator's under- a load do we have to apply MORE power than the original input? If the load was 95W of power, and the mechanical input to the generator is 100W continually going on. Is the system going to work fine? Or is there something here that I'm missing?
@Shane_B @Carl_Pham @experimentX @Jemurray3
@.Sam.
@jhonyy9
are you taking a gen ideal generate.since only in such generators efficiency is 100 percent
I can remember the radio set AN/GRC-46 mounted in a 3/4 ton truck with a shelter. The transmitter was the T-195, it was powered by a battery/generator the Leece Neville 24 volt system. Whenever the radio operator keyed that transmitter, the engine would "lug"down as the generator needed increased mechanical energy to produce the additional amps required by the increased load.
@radar that means that the load is rated far more greater than what you're putting in. However, if the mechanical input was easily greater than the load it would work fine. My examples showed that if you inputted 100W's of mec. power and converted it to electrical power rated 95W, the 95Watts is the load's requirement to work fine. However, if the load was 150W and the input is 100 that means you simply need to increase the MEC power to overcome the load + all the resistant forces. I think its all based on simple calculations on logic. If you have a box that is 5Kg , you'd need to have 6N's of force to lift it. If you had 2N of force I think you can't lift the box properly, try to relate that to my situation and you'd see :) I think things are starting to make sense!
I think you are on the right track.
@radar thanks.
I thought we covered this pretty well 2 months ago! :) http://openstudy.com/study#/updates/50492ccae4b003bc1204513f
Ow my! I forgot already, I've been studying a lot of things back and forth and forgot about this one...
Yea @Shane_B I got this understood very very well. I think that the problem was all due to the confusion I had. But my final response to @radar is pretty much my full understanding of it. Can you read it? Just to be sure? Thanks.
Your last response looks fine to me :)
I guess my understandings good! @Shane_B thanks!
Join our real-time social learning platform and learn together with your friends!