Question

. a bus travel at 36 km/h and arrives in its destination half an hour late. If it travels at 42 km/h, it arrives at the same destination half an hour earlier. Find the journey distance.

Answer 1

@mr.tobby Both the cases the distance is the same, Let time taken usually be t hours
First case the bus arrives half an hour late. So time taken by it (t+0.5) hours
Second case the bus arrives half an hour early. Time taken (t-0.5) hours
Distance covered in first case
\[D=36(t+0.5)\]
Distance covered in second case
\[D=42(t-0.5)\]
Equate both these
\[36(t+0.5)=42(t-0.5)\]
Can you find t from this ? @mr.tobby

Answer 2

t=6.5 ? then?

Answer 3

yes, now find distance using any of the two equations.

Answer 4

use D=42(t-0.5) and D = 42(t+0.5)

Answer 5

Check your second equation :)

Answer 6

wrong typed,:)

Answer 7

Use any of the two both will give you the same answer :)