Question

Perform the indicated operations.y^4-16/y+2 divide y^2+4/5

Answer 1

5(y - 4)
5(y + 4)
5(y - 2)

Answer 2

Factor everything that you can so when you divide you can easily see if there are any factors that cancel one another out.

Answer 3

i need help please

Answer 4

@mayankdevnani

Answer 5

@hero

Answer 6

use (a^2 - b^2) = (a-b)(a+b)

notice that
y^4-16

matches this pattern. \(y^4 \) is \(y^2 \cdot y^2\) or \( (y^2)^2 \) and 16 is \(4^2\)

Answer 7

@Zarkon

Answer 8

@ saifoo.khan (Ambassador

Answer 9

@saifoo.khan

Answer 10

\[\frac{y^4-16}{y+2}\div\frac{y^2+4}{5}\]\[\frac{y^4-16}{y+2}*\frac{5}{y^2+4}\]\[\frac{(y^2-4)(y^2+4)}{y+2}*\frac{5}{y^2+4}\]\[\text{So you get..}\]\[\frac{5(y^2-4)}{y+2}\]\[\text{Now solve and you would get the answer.}\]

Answer 11

@robert2

Answer 12

a;5(y - 4)
b;5(y + 4)
c;5(y - 2) what is tha anwrer i confusing

Answer 13

\[\frac{5((y+2)(y-2)}{y+2}=5(y-2)\]

Answer 14

is true

Answer 15

If there is something confusing,ask me.. :)

Answer 16

C is the answer..

Answer 17

You are welcome..