PLZ HELP...... if an object is dropped from a height of 144 feet, the function h(t)=-16t^2+144 gives the hight of the object after t seconds. when will the object hit the ground.
A.9s
B.6s
C.1.5s
D.3s
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OpenStudy (anonymous):
"hit the ground" means h(t)=0.
Solve \(144-16t^2=0\).
OpenStudy (anonymous):
sorry the 16 is -
OpenStudy (anonymous):
So...
\(16t^2=144\)
What might t be? (You can ignore negative values.
OpenStudy (anonymous):
huh
OpenStudy (anonymous):
Have you ever solved a quadratic equation before?
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OpenStudy (anonymous):
no
OpenStudy (anonymous):
Then reason your way through it.
You have perfect squares on each side of the equals sign, so take the square root of each side.
OpenStudy (anonymous):
square of 16 is 4 and square of 144 is 12
OpenStudy (anonymous):
Yep, so what's left?
OpenStudy (anonymous):
4 and 12
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OpenStudy (anonymous):
would you divid the two numbers
OpenStudy (anonymous):
Yes, you need to get t by itself on one side of the equals sign.
OpenStudy (anonymous):
so then it would be three
OpenStudy (anonymous):
Yep. Three what? What is the question asking for?
OpenStudy (anonymous):
You can also verify the solution in the original function:
\(h(t)=-16t^2+144 \space \rightarrow h(3)=-16(3)^2+144=0.\)
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