PLZ HELP...... if an object is dropped from a height of 144 feet, the function h(t)=-16t^2+144 gives the hight of the object after t seconds. when will the object hit the ground. A.9s B.6s C.1.5s D.3s
"hit the ground" means h(t)=0. Solve \(144-16t^2=0\).
sorry the 16 is -
So... \(16t^2=144\) What might t be? (You can ignore negative values.
huh
Have you ever solved a quadratic equation before?
no
Then reason your way through it. You have perfect squares on each side of the equals sign, so take the square root of each side.
square of 16 is 4 and square of 144 is 12
Yep, so what's left?
4 and 12
would you divid the two numbers
Yes, you need to get t by itself on one side of the equals sign.
so then it would be three
Yep. Three what? What is the question asking for?
You can also verify the solution in the original function: \(h(t)=-16t^2+144 \space \rightarrow h(3)=-16(3)^2+144=0.\)
oh thank you very much for your help
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