Question

antiderivative(18)/(5-x) = kln[5-x]+c
Find the exact value of k that makes the antidifferentiation formula true.

Answer 1

i got 18 but is wrong

Answer 2

@ jorourk3
\[\int\limits_{}^{}\frac{ 18 }{ 5-x }=-18\ln(x-5)+C\]=kln[5-x]+c
seems like k=-1 ? yes or no?

Answer 3

im sorry its -18
:D

Answer 4

k would be -18 then by what your saying...wouldnt it?
that is also absolute value signs around ln[x-5] btw...does that change it from what you are saying?

Answer 5

its correct! thanks!
i dont understand why it is negative though?

Answer 6

its negative bec you let u=5-x
then du= -dx

Answer 7

or du/dx=-1

Answer 8

ok thanks....can you help me with a similar one please? :)

Answer 9

ok yw ..:D
just post them again so that others can see them