antiderivative(18)/(5-x) = kln[5-x]+c
Find the exact value of k that makes the antidifferentiation formula true.

Question

antiderivative(18)/(5-x) = kln[5-x]+c
Find the exact value of k that makes the antidifferentiation formula true.

anonymous · Answer

i got 18 but is wrong

anonymous · Answer

@ jorourk3
$$\int\limits_{}^{}\frac{ 18 }{ 5-x }=-18\ln(x-5)+C$$=kln[5-x]+c
seems like k=-1 ?  yes or no?

anonymous · Answer

im sorry its -18
:D

anonymous · Answer

k would be -18 then by what your saying...wouldnt it?
that is also absolute value signs around ln[x-5] btw...does that change it from what you are saying?

anonymous · Answer

its correct! thanks!
i dont understand why it is negative though?

anonymous · Answer

its negative bec you let u=5-x
                            then du= -dx

anonymous · Answer

or du/dx=-1

anonymous · Answer

ok thanks....can you help me with a similar one please? :)

anonymous · Answer

ok yw ..:D
just post them again so that others can see them