A catapult launches a boulder with an upward velocity of 112 ft/s. The height of the boulder, h, in feet after t seconds is given by the function h= -16t^2+112t+30. How long does it take the boulder to reach its maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary. A. 7 s; 30 ft B. 3.5 s; 366 ft C. 3.5 s; 618 ft D. 3.5 s; 226 ft A, B, C, or D? Please explain :)
perhaps you should try as possible solution options. http://openstudy.com/users/zigzagoon2000#/updates/509de176e4b013fc35a15bed
do you know how to differentiate...?
No I do not.
ok... do you know how to find the line of symmetry for a parabola..?
No.
ok... well that rules out the 2 easiest methods for this question. My suggest is use a graphing package and graph the curve...
Do you know the answer?
I know the time when the max height occurs..
What is the time when the max height occurs?
that doesn't help you understand how to solve it..
I do not know how to solve it and it will take me years to work my way up to that knowledge.
here is the easiest solution graph the curve here is a free site that you can use... the max height will be the top of the parabola.. http://www.geogebra.org/cms/
I will definitely add that to my bookmarks, but do you know the answer to this question?
Join our real-time social learning platform and learn together with your friends!