If the area of a square is two more than twice the length of its diagonal then the length of one side of the square is........
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
where are u stuck ? what u tried ?
OpenStudy (hba):
I got the answer root(2)-2 ?
hartnn (hartnn):
oh let me calculate and check.....
OpenStudy (hba):
Ok thanks :)
hartnn (hartnn):
is this your equation :
s^2-2root2 s -2 = 0
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (hba):
S^2-2roor2s+2=0
OpenStudy (hba):
root*
hartnn (hartnn):
i get root 2 +2
hartnn (hartnn):
how did u get -2 ?
OpenStudy (hba):
I just really dont know this gap year has made my mind rusty :( Let me check again and tell you :)
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
just get the equation right
S^2-2roor2s+2=0 is incorrect
hartnn (hartnn):
s^2-2root2 s -2 = 0
OpenStudy (hba):
Thanks Alot. :)
hartnn (hartnn):
oh, welcome.
but did u get your error ?
OpenStudy (hba):
Well a little explanation would help ?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
hartnn (hartnn):
sure, area of a square is two more than twice the length of its diagonal
means if we add 2 to
'twice the length of its diagonal'
then we can equate
area of square and 'twice the length of its diagonal'
so we get
s^2 = 2root 2 s \(\huge +2\)