If the simultaneous equations \[y= x^{2}-k\] y=x have only one solution, find k. A. -1 B. \[-\frac{ 1 }{ 4 }\] C. -4 D. \[\frac{ 1 }{ 4 }\] E. 1
just put y=x in y=x^2-k what u get ?
x=x^(2)-k k=x(x-1) what's the answer?
the equation is x^2 -x-k=0 now u know how to find k if there is only one solution of quadratic equation ?
just sub the answer into the equation? -.-
is it B?
yes, thats a way , but easier would be to equate discrimant to 0 know what discriminant is ?
b^(2)-4ac (-1)^(2)-4(1)(-k) ?
yes, equate that to 0
1+4k=0 k= ?
-1/4 thank you and I have many questions, would you kindly help me ?
i will surely try...i am helping 2-3 ppl at a time...
oh...sorry...I think I can ask another ppl... you are too busy :P
open it as a new question...if not me, some1 will surely help you :)
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