Express the sum using summation notation. Use the lower limit of summation given and k for the index of summation 6+9+12+15+...+45

Question

anonymous · Answer

@Soccergurl2002

anonymous · Answer

r u there

anonymous · Answer

plz give me medal if i helped

anonymous · Answer

soryry i didnt see ur response

anonymous · Answer

u mean u did'nt understand?

anonymous · Answer

the correct answer is $$\sum_{14}^{3k+3}$$ i just dont know how they got it

anonymous · Answer

oh i mean 14 is on the top, and k=1 is on the bottome and to the right is 3k+3

anonymous · Answer

ok  now wait that's same as what i have said let me tell u now

anonymous · Answer

ok

anonymous · Answer

14  is  total number of terms between  6 and 45 ok

anonymous · Answer

$$\sum_{k=1}^{14}3k+3$$ that would be the correct answer , why 14?

anonymous · Answer

u would have   $$\sum_{1}^{14}(3k+3) $$
for k =1  
     6
for k=2  
   9   
for  k=3
   12   
.         . 
.         .
for k=14
   45     
    $$\sum_{a}^{b}$$ this sign indicates there is plus sign between theses terms  so the serries is same    6+9+12............+45

anonymous · Answer

it's easier to right the whole serries in sigma notation then writing it like a1+a2+.....+an

anonymous · Answer

ok

anonymous · Answer

@Fazeelayaz a medal from my side

anonymous · Answer

thanks for the help

anonymous · Answer

@Fazeelayaz

anonymous · Answer

yes thanks for these medals i will show them to my girl friend