Question

i^21+i^32-i^67 =

Answer 1

@hartnn

Answer 2

i=?

Answer 3

i=underroot(-1)

Answer 4

i^2=?

Answer 5

-1

Answer 6

i^3=?

Answer 7

i^3=?

Answer 8

i^4=?

Answer 9

i^3=-i ,i^4=1

Answer 10

i^5=?
so u see the pattern ?

Answer 11

I understand the pattern but when i get higher powers i get confused :(

Answer 12

\(\huge i=\sqrt{-1} \\ \huge i^2=-1 \\ \huge i^3=-i \\ \huge i^4=1 \\~ \\~ \huge i^5=\sqrt{-1} \\ \huge i^6=-1 \\ \huge i^7=-i \\ \huge i^8=1\\~\\~ \huge i^9=\sqrt{-1} \\ \huge i^{10}=-1 \\ \huge i^{11}=-i \\ \huge i^{12}=1\)

Answer 13

so i raised to any 4th power =1

Answer 14

write i^21 as
i*i^20
what is i^20 = ?

Answer 15

1 ?

Answer 16

so i^21 = ?

Answer 17

i

Answer 18

yes, what about i^32 = ?

Answer 19

1

Answer 20

try i^67

Answer 21

i^3

Answer 22

thats correct, and i^3= ?

Answer 23

-underroot(-1)

Answer 24

thats -i
and final answer = ?

Answer 25

1

Answer 26

yup.
clear with all steps ?

Answer 27

yeah thanksalot :)

Answer 28

wait...
i+1-(-i)=?

Answer 29

No it is a plus not a minus sorry :)

Answer 30

I wrote the question wrong

Answer 31

then its 1

Answer 32

Yeah :)