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Mathematics 10 Online
OpenStudy (hba):

Question...

OpenStudy (hba):

If \[z _{1}=1-i ,z_{2}=7+i\] then the modulus of \[\frac{ z _{1}-z _{2} }{ z _{1}z _{2} }\]

OpenStudy (hba):

looks like no one is interested in helping me :D

OpenStudy (hba):

@ash2326 @phi

OpenStudy (hba):

I tried to Solve it And got the final expression as \[\frac{ -6-2i }{ 8-6i }\] Do I apply the modulus now ?

OpenStudy (ash2326):

First find z1-z2 and z1 z2 Then take the modulus of both and divide

OpenStudy (hba):

@ash2326 I think you did not see my comment

OpenStudy (hba):

I moreover simplified it to \[-3-i/4-3i\]

OpenStudy (ash2326):

Now find modulus of -3-i and find modulus of 4-3i and divide both

OpenStudy (hba):

Taking a conjugate would help ?

OpenStudy (hba):

Well @ash2326 I tried it that way but it didn't help :(

OpenStudy (ash2326):

Are you getting a wrong answer?

OpenStudy (anonymous):

multiply numerator and denominator by 4+3i it will make the problem more easier

OpenStudy (hba):

@ash2326 Yes

OpenStudy (hba):

@niksva This is what we call a conjugate and i was asking that only ?

OpenStudy (ash2326):

Answer is \[\frac{\sqrt {10}}{5}\] What did you get?

OpenStudy (anonymous):

@hba i know what is meant by conjugate i m telling u to rationalize the function

OpenStudy (hba):

\[2\sqrt{2}/7\]

OpenStudy (hba):

LoL :D

OpenStudy (ash2326):

You made a mistake here. Let me show \[-3-i/4-3i\] \[|-3-i|=\sqrt{(-3)^2+(-1)^2}=\sqrt{10}\] \[|4-3i|=\sqrt{(4)^2+(-3)^2}=\sqrt {25}=5\] so you'd get \[\frac{\sqrt{10}}{5}\]

OpenStudy (hba):

Thanks A Lot @ash2326

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