Find the equation of the line which cuts the x-axis at 5 and the y-axis at -2
2 points are (5, 0) and (0, -2). The first is (x1, y1) and the second is (x2, y2), both in the form (x, y). First, get the slope from:\[\frac{ y _{1}- y _{2} }{ x _{1}-x _{2} } = m\]where "m" is the slope. Show your work, get the slope, and then we can go to the next step.
How are you coming along with this?
\[\frac{ 0-2 }{5-0 }=\frac{ -2 }{ 5 }\]
oh it´s supposed to be 2 instead of -2
Good! Now I'll get you the next step..
Now that you have m = 2, the point-slope equation for the line is:\[y - y _{1} = m(x - x _{1})\]You can either leave the equation is this form (after making the substitutions using either point ) of rearrange into the standard or slope-intercept form of the line.
\[\frac{ y-0 }{x-5 }=\frac{ 2 }{ 5 }\]
5(y-0)=2(x-5)
5y-0=2x-10
2x-5y=10
Great work! Well done!
Thanks for your help!!
yw!
Good work and good luck to you! If you like my work, hit "best response"
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