Find the second derivative of the function f(x) = log5 x^3.
I know the first derivative is \[\frac{ 3 }{ xln5 }\] but then i'm stuck...
If I were you I'd start by using the change of base formula to convert the logarithm to a quotient of natural logarithms, which are really easy to derive. OR Using what you just typed: 3/ln5 is a constant isn't it?
What do you think now, in light of the rules you may have learned?
Well I think I need to use the chain rule... but I don't know for sure... And I have no idea what the derivative of xln5 would be...
Constant multiple rule. What's the derivative of 3/x?
-3/x^2?
Yes, and since ln5 is a constant, you can just insert it into the denominator. Maybe I made this difficult.\[\frac{ d }{ dx }(\frac{ 1 }{ x })=\frac{ -1 }{ x ^{2} }\]\[\frac{ d }{ dx }(\frac{ 3 }{ xln 5})=\frac{ 3 }{ \ln 5 }* \frac{ d }{ dx }(\frac{ 1 }{ x })\]because 3/ln5 is a constant. Check it on a calculator if you like
hmmm... the answer i'm given is \[-\frac{ 3 }{ \ln5 } x^-2\]
Think about it: What does a negative exponent do?
oh pellet... makes it a fraction.
Yep. Btw, are you at all interested in using the change of base formula on future problems?
yes i am interested.
i need to learn it... well i'm supposed to already know it. i'm a little behind in my class.
That's all right. Math is something you can learn any time\[\log_{b}x=\frac{ \ln x }{ \ln b } \] or (treating ln b as a constant)\[=\frac{ 1 }{ \ln b }(\ln x)\] This saves you from learning a rule just for derivatives of logs in other bases. The derivatives of natural logs are really easy.
If you need any more help, just mention me (that @ thing) or message me
okay. thanks a lot for your help today.
yw
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