a flea's jump can be modeled by the function y = -0.073x(x-33) where x is the horizontal distance (in cm) and y is the corresponding height (in cm). How far did the flea jump? What was the flea's maximum height?
are they askiing for the distance from when the flea would start from the ground or the distance from the height to the ground
both
for the horizontal distance you need to find the values of x where the height is zero... this will give the horizontal distance. So solve \[0 = -0.073x(x - 33)\] the equation for the path is a quadratic so the flea jumps in a parabolic arc. to find the vertical height you can either distribute and get the equation \[y = -0.073x^2 + 2.409 x\] find the line of symmetry \[x = \frac{-b}{2a}\] a = -0.073 b = 2.409 the max height can be found by substituting this value into the original equation. or you can say the vertical height is a max at half the horizontal distance and substitute that value into the original equation. or find the 1st derivative ( if you know calculus) and solve for x.... then substitute that value into the original equation.
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