Mathematics
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OpenStudy (anonymous):
Find the GCF of the first two terms and the GCF of the last two terms of the polynomial.
5h3 + 20h2 + 4h + 16
A. 5h2, 16
B. 5h3, 4
C. 5h2, 4
D. h2, h
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OpenStudy (zzr0ck3r):
what can devide the first and second terms?
OpenStudy (anonymous):
5 n 4 then 4n4
OpenStudy (anonymous):
or 2 and 8 for 16
OpenStudy (zzr0ck3r):
hint: 5h^3+20h^2 = 5h^2(h+4)
OpenStudy (anonymous):
so 5h^3 +20h^2
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OpenStudy (anonymous):
You could also look at it as (5h^3+20h^2)+(4h+16). Factor out the first () and then factor out the second ()
OpenStudy (anonymous):
factor them how
OpenStudy (anonymous):
You are looking for something common with 5 and 20, and also h^3 and h^2.
OpenStudy (anonymous):
wouldnt the common be five
OpenStudy (anonymous):
yes, and on the h^3 and h^2?
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OpenStudy (anonymous):
h
OpenStudy (anonymous):
close then you would have 5h(1h^2+4h), looks like you can take something out again?
OpenStudy (anonymous):
the 1h^2
OpenStudy (anonymous):
does the 4 have an h^2 that can be taken out?
OpenStudy (anonymous):
ok so that leaves 5h^2
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OpenStudy (anonymous):
There you go, good job so on the first one you have 5h^2(h+4).
Now what would you take out the second one (4h+16)?
OpenStudy (anonymous):
4h
OpenStudy (anonymous):
Not just elimanating your possibilities did you see that a 5h^2 was common in both?
OpenStudy (anonymous):
does the 16 have an h to take out?
OpenStudy (anonymous):
or no the 4 does
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OpenStudy (anonymous):
can you take 4 out of both?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
so what would you be left with if you took a 4 from both?
OpenStudy (anonymous):
h
OpenStudy (anonymous):
5h^2 and 16
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OpenStudy (anonymous):
and what would be left over of the 16?
OpenStudy (anonymous):
can you get 16 out of 4?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
|dw:1352603446925:dw|
Can you take 16 out of 4?