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Mathematics 12 Online
OpenStudy (anonymous):

Find the GCF of the first two terms and the GCF of the last two terms of the polynomial. 5h3 + 20h2 + 4h + 16 A. 5h2, 16 B. 5h3, 4 C. 5h2, 4 D. h2, h

OpenStudy (zzr0ck3r):

what can devide the first and second terms?

OpenStudy (anonymous):

5 n 4 then 4n4

OpenStudy (anonymous):

or 2 and 8 for 16

OpenStudy (zzr0ck3r):

hint: 5h^3+20h^2 = 5h^2(h+4)

OpenStudy (anonymous):

so 5h^3 +20h^2

OpenStudy (anonymous):

You could also look at it as (5h^3+20h^2)+(4h+16). Factor out the first () and then factor out the second ()

OpenStudy (anonymous):

factor them how

OpenStudy (anonymous):

You are looking for something common with 5 and 20, and also h^3 and h^2.

OpenStudy (anonymous):

wouldnt the common be five

OpenStudy (anonymous):

yes, and on the h^3 and h^2?

OpenStudy (anonymous):

h

OpenStudy (anonymous):

close then you would have 5h(1h^2+4h), looks like you can take something out again?

OpenStudy (anonymous):

the 1h^2

OpenStudy (anonymous):

does the 4 have an h^2 that can be taken out?

OpenStudy (anonymous):

ok so that leaves 5h^2

OpenStudy (anonymous):

There you go, good job so on the first one you have 5h^2(h+4). Now what would you take out the second one (4h+16)?

OpenStudy (anonymous):

4h

OpenStudy (anonymous):

Not just elimanating your possibilities did you see that a 5h^2 was common in both?

OpenStudy (anonymous):

does the 16 have an h to take out?

OpenStudy (anonymous):

or no the 4 does

OpenStudy (anonymous):

can you take 4 out of both?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so what would you be left with if you took a 4 from both?

OpenStudy (anonymous):

h

OpenStudy (anonymous):

5h^2 and 16

OpenStudy (anonymous):

and what would be left over of the 16?

OpenStudy (anonymous):

can you get 16 out of 4?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

|dw:1352603446925:dw| Can you take 16 out of 4?

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