Question

solve by completing the square 4x^2-4x-63=0

Answer 1

really?

Answer 2

really?

Answer 3

ok

Answer 4

just want you to check my answer

Answer 5

\[4x^2-4x-63=0\]
\[4x^2-4x=63\]
\[x^2-x=\frac{63}{4}\]
\[(x-\frac{1}{2})^2=\frac{63}{4}+\frac{1}{4}=\frac{64}{4}=16\]
\[x-\frac{1}{2}=\pm\sqrt{16}=\pm4\]
\[x-\frac{1}{2}=4\iff x=\frac{9}{2}\]
\[x-\frac{1}{2}=-4\iff x=-\frac{7}{2}\]

Answer 6

\[(2x-9)(2x+7)=0\] may have been easier

Answer 7

yeah but i was told to solve it by completing the square

Answer 8

wait where did that 1/4 come from

Answer 9

that you added to 63

Answer 10

plz tell

Answer 11

nvm just realized