Mathematics
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OpenStudy (anonymous):
locate the absolute extrema of the function (if any exist) over the interval. f(x)=2x-3 [0, 2]
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OpenStudy (anonymous):
Familiar with the derivative ? can you take the derivative of f(x), if so, what do you get ?
OpenStudy (anonymous):
2
OpenStudy (anonymous):
what are the roots of 2 ? where does it cross the x axis
OpenStudy (anonymous):
at y=0???
OpenStudy (anonymous):
can y ever be zero if it always equals 2 ?
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OpenStudy (anonymous):
nope
OpenStudy (anonymous):
any max extrema then ?
OpenStudy (anonymous):
abs*
OpenStudy (anonymous):
im kinda of confused by ur question :[
hartnn (hartnn):
u got x=2
put it in f(x) to find the extrema
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OpenStudy (anonymous):
1 ?
hartnn (hartnn):
thats correct :)
OpenStudy (anonymous):
thats it?
hartnn (hartnn):
wait.
for extrema, u take derivative and equate it to 0
means you do, f'(x)=0
but you got f'(x) = 2
hence there is no extrema.....
OpenStudy (anonymous):
but you c in my book it has an answer or answers of min (0,-3) and max (2,1)
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hartnn (hartnn):
i know, there is no global extrema,
and so, here we find local extrema by substituting the endpoints.
so put x=0 and x=2
and find f(x)
hartnn (hartnn):
*local = absolute
hartnn (hartnn):
whenever we don't get global extrema, we put endpoints....remember this.
OpenStudy (anonymous):
i am utterly confused :[
hartnn (hartnn):
lets start over ?
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OpenStudy (anonymous):
yes please :]
hartnn (hartnn):
ok, absolute extrema means max or min points in the given interval.
hartnn (hartnn):
now to find min or max values, you take derivative of function and set it =0
hartnn (hartnn):
then you get values of x for which the function is min/max.
if f'(x) cannot be equal to 0, then there is no global extrema
ok ?
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
or if its like 1/0 right?
hartnn (hartnn):
in that case, we can find 'local' or 'absolute' values at the endpoints, they become min/max values.
hartnn (hartnn):
yes.
OpenStudy (anonymous):
so 2=0
hartnn (hartnn):
i can't think of an example when u get 1/0 after taking the derivative.
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hartnn (hartnn):
here , you get f'(x) =2
we cannot equate this to 0
hartnn (hartnn):
because 2 can never =0
hence there is no extrema, or as we say, no global extrema
hartnn (hartnn):
but we can find absolute extrema, that is min/max in GIVEN INTERVAL
OpenStudy (anonymous):
how do we find these?
hartnn (hartnn):
one of the end-point is x=2
there what is f(x) = ?
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OpenStudy (anonymous):
1?
hartnn (hartnn):
so the point is (2,1) and this is one of the extrema
we don't know yet whether this is max or min
hartnn (hartnn):
now put other end point, x=0
what is f(x)
OpenStudy (anonymous):
wait where did we get x=0?
hartnn (hartnn):
[0,2]
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OpenStudy (anonymous):
your interval [0,2]
hartnn (hartnn):
thats where i got x=2 also earlier
OpenStudy (anonymous):
ooooooooo okay there will be 3 extrema right???
hartnn (hartnn):
how come 3 ?
one for x=2, and one for x=0
OpenStudy (anonymous):
o yeah my bad -_- :]
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OpenStudy (anonymous):
we do the same for 0 right ???? plug it into the orig equation? right?
OpenStudy (anonymous):
you could just say there's no global min/max since the function is linear right?..
hartnn (hartnn):
yes.
hartnn (hartnn):
to both
OpenStudy (anonymous):
k, thanks. double checking.
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hartnn (hartnn):
now put other end point, x=0
what is f(x)
OpenStudy (anonymous):
-3?
hartnn (hartnn):
so the other point is ?
hartnn (hartnn):
and which one should be min and which one should be max ?
OpenStudy (anonymous):
0,-3 is min the other is max?
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hartnn (hartnn):
yes, thats correct.
clear with every step ?
OpenStudy (anonymous):
yes sir or mam! :]
OpenStudy (anonymous):
thanks so much!
hartnn (hartnn):
your welcome ^_^
OpenStudy (anonymous):
:]