please help! please!!! Write a summary of this journal.,
can u help me @KarolinaJosephine ???
what do you need?
key points
that's a lot of reading
yes :(, it's so confusing
I'm sorry
ok..., no problem :)
I am weak in summary about chemistry .... Let me try....
ok.., @kryton1212 :)
around how many words?
In the form of tables and graphs, the optical constants and photoelectric emission for the four alkali metals Cs, Rb, K, and Na in the spectral range 250-630 nm inside which the volume-plasmon wavelengths λp and the surface-plasmon wavelength λs are situated. The metals are prepared in the form of optically thick layers condensed in ultrahigh vacuum (10-11 torr) on targets cooled at 77 °K. When maintained at 77 °K, the layers show a spectral selectivity independent of the state of polarization of the exciting monochromatic radiation. Upon reheating at 195 °K or higher, a very pronounced vectorial selectivity appears, accompanied by diminution of the photo-emission. Values given in the tables and graphs are reproducible within a fair approximation, stated in each case. From the "optical" conductivity curves σ=f(ℏω), it is not possible to identify an absorption process due to inter-band transitions (Wilson-Butcher theory). The plot of the real part of the dielectric constant against the square of the exciting radiation wavelength ε1=f(λ2) is perfectly linear for all reheated layers, thus allowing use of the Cohen and the Fowler formulas in the calculation of σ, λp, the "optical" mass, the polarizability, and the work function for several temperatures. The normal reflectivity curves for the reheated layers show a point of inflection for λ=λP. For the same layers, the quantum efficiency of the photo-emission shows a minimum for λ=λp, particularly well marked for the lighter metals. Finally, the work-function values at 0 °K extrapolated from our experimental results by the Fowler process, are shown to have two values W∥ and W⊥ whenever the layer investigated exhibits vectorial selectivity; the difference W∥-W⊥ is only a few hundredths of an electron volt but is quite reproducible. hope can help you.........I am weak in English and Chemistry :P I need to have lunch first, see you later.
thank u so much @kryton1212
@kryton1212 happy lunch for u.., ;)
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