2x+3y=6 can be expressed in terms of conjugate coordinates as :

Question

hba · Answer

@thivitaa

hba · Answer

@campbell_st

campbell_st · Answer

well it doesn't make a lot of sense to me

the slope intercept form is 

y = -2/3x + 2

hba · Answer

Let me give you the options @campbell_st 

z+3/2i(z-zbar)=6,zbar+3/2i(z-zbar)=6,z+zbar-3/2i(z-zbar)=6,z-zbar+3/2i(z-zbar)=6

hba · Answer

So @thivitaa

thivitaa · Answer

cant gt the ans....bad at math..:)

hba · Answer

Ok

hba · Answer

@dpaInc

hba · Answer

@sirm3d

sirm3d · Answer

what does conjugate coordinates mean?

hba · Answer

Have You ever studied Complex numbers ?

sirm3d · Answer

yes i did. and i can't remember conjugate coordinates. can you refresh me on this?

hba · Answer

Ok,Any pair of complex numbers a+ib and a-ib have a product which is real,since (a+ib)(a-ib)=a^2-abi+abi-b^2i^2=a^2+b^2.
Such complex numbers are called "conjugate" and each is the conjugate of the other.If a+ib is denoted by z,then its conjugate a-ib,is denoted by zbar. 


I hope this helps.

sirm3d · Answer

@hba i get it. the answer is $$\huge z+z^b-\frac{ 3 }{ 2i }(z-z^b)=6 $$ where z^b is the conjugate of z. for the details. if we let z=x+yi and z^b = x-yi then $$\huge x=\frac{ z+z^b }{ 2 }$$ and $$\huge y=\frac{ z-z^b }{ 2i }$$ just replace x and y the their equivalent expressions