Question

If the diagonal if a square is (50-12 square root of 2) cm, what is the area of the square?

Answer 1

@jiteshmeghwal9 pls help again :)) sorry to disturb you

Answer 2

Diagonal of the square = Side x sqrt(2)
Area of the square = (side)^2

These are the basic theorems we should use.
Associating are of the square in terms of it's side, which is associated to the diagonal.

Answer 3

D = 50 - 12sqrt(2)
D = (s)sqrt(2)
A = s^2

A = (50-12sqrt(2))^2/2

Answer 4

\[A = {({50-12\sqrt{2})}^2}/2\]

Answer 5

that cant be true if the side is\[50-12\sqrt{2}\]

Answer 6

I mean diagonal
is the diagonal \[5-12\sqrt{2}\]
or
\[(5-12)\sqrt{2}\]

Answer 7

A = 545.47 cm^2

Answer 8

If we consider \[50 - 12\sqrt{2}\] as the diagonal

Answer 9

if it is\[50-12\sqrt{2}=(\frac{50}{\sqrt{2}}-12)\sqrt{2}\]
side\[50/\sqrt{2}-12\]
\[A=(\frac{ 50}{\sqrt{2}}-12)^2\]

Answer 10

Still the same answer

Answer 11

what is the answer?

Answer 12

A = 545.47 cm^2