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Can anyone teach me how to solve: 3^x=1 Without LOGS!!!
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1 can be written as 3^0 so 3^x = 3^0 on comparing x=0
@sufiyancs is it right????
Ohhh... Darn i forgot the basic rule... hehehe thanx @niksva
:)
Amm @niksva so how are we gonna solve 16^z=2
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write 16^z as 2^4z bcoz 2^4 = 16
rest u know how to do it
\[\frac{3^x}{3^x}=1\] \[3^{x-x}=1\] \[3^{0}=1\] \[x=0\]
So u mean 4z=1 z=1/4 Right... Therefore, 16^(1/4) = 2 Thanxxx Again!
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