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Please help explain the steps to this question for me.
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Find the derivative y' of the function by the equation \[e^{xy}=2(x+y)\]
i am up to this point: \[e^{xy}(xy'+y)=2+2y'\]
my prof has this done out and his next step confuses me.. it looks like this: \[xe^{xy}y'+ye^{xy}=2+2y'\]
yu shud have done the logarithmic step at first then take the derivatives on both sides in that way u get rid of the e
can you explain his next step for me please?
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i posted it just above what you said.
and e is in the final answer ...
so i don't think i can jsut get rid of it.
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