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Mathematics 8 Online
OpenStudy (anonymous):

lim -> 0 sin(2x) /(x*cos(x) ) help

OpenStudy (anonymous):

sin (2x) = 2sin(x)cos(x) so sin(2x) /(x*cos(x) =2sin(x)cos(x)/x*cos(x)=2sinx/x which as x->0 goes to 1

OpenStudy (anonymous):

no, answer is 2

OpenStudy (anonymous):

ups sry, forgot about 2 multuplying: lim 2sinx/x=2*1=2 x->0

OpenStudy (anonymous):

don't undestand you

OpenStudy (anonymous):

sin (2x) can be written like: sin (2x) = 2sin(x)cos(x) substituting this expretion in the original one: sin(2x) /(x*cos(x) =2sin(x)cos(x)/x*cos(x)=2sinx/x taking limits, and noticing that lim as x->0 of sinx/x=1: lim 2sinx/x=2*1=2 x->0

OpenStudy (anonymous):

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