NEWTON METHOD FIND SIX DECIMALS : SINX+X-1=0 WHERE X1=0
First find the derivative
Also the equation for newton's method is as follows...
\[x _{n+1}=x_n-\frac{ f(x_n) }{ f'(x_n) }\]
YEAH I KNOW THE DERIVATE IS COSX+1
BUT WHATS NEXT PLUG 0 IN THE EQUATION?
No, approximately, what x-value allows f(x) to equal 0?
WELL X1=0
LETTING THIS BE SO PLUG IT IN THE EQ?
Ok, yes you can plug in zero and it will yield the same result.
I HAVE FOR X1= -1/2
should be positive 1/2
Be careful when plugging problems like these into your calculator...
I STILL GET NEGATIVE EXAMPLE 0-SIN0+0-1 DIVIDED BY COS0+1
My mistake, you are correct.
Now plug in -1/2 in place of xbase 1 and do so until you find a repeating answer....
Keep replacing xbase1 with the most recent y-value
Sorry for not being better help
SO FOR THE NEXT X2= I PLUG -1/2
yes, and the value given by x2 is x3
repeat the calculation until you are given a repeating y-value...it helps to use the table feature on a graphing calculator if you have one.
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