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Calculate the pH of 6.8 × 10-8 M HCl. Report your answer to the hundredths place.
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ph = -log[H+] hint [H+] can be found out from the concentration of HCl
@Kryten
yes?
Hcl -----> H^+ + Cl^-
So H+ = 6.8 × 10-8
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Am i correct ?
yup and from there you see that n(HCl) = n(H+) so [H+] = [HCl]
Nw PH = -log (6.8 × 10-8) pH = 8 - log6.8 correct??
nope pH = - log (6,8*10^-8) or if you want pH = - log 0,000000068 ;)
ok.....thxxx....) Sir..)
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not a problem ;)
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