Question

a certain radioactive substance loses one third of its original mass in 5 days. find its half-life using the half-life function N(x) = c(0.5)^(x/h)

Answer 1

m-m/3=m/2^t
t=log_2(1.5)
HT=5/t

Answer 2

why is it m-m/3?

Answer 3

lost one third

Answer 4

okay but if i had to use the equation given, would it be N(x)=(1/3)(0.5)^(x/5)

Answer 5

I don't know what is that !

Answer 6

thats the equation i was given to use ):