Question

A bullet is fired horizontally from the top of a building with a muzzle velocity of 150 m/s.A similar bullet dropped from the top of the same building, takes 4 sec to reach the ground. How far forward does the first bullet go before it hits the ground?Which bullet hits the ground first? What is the average speed of the dropped bullett?

Answer 1

help me pleasee:(

Answer 2

somebody help me lol

Answer 3

1s=9,81ms/^2+....2s=2x...+. 3s=3x.....+ 4s=4x.... =....There you have the that answer. Unless the second bullet hits a mountain it won't hit the ground first:).

Answer 4

im confused is the first answer 600 meters

Answer 5

uuhm well first you have to figure out how far from the top until the gorund.

Answer 6

answer lies in my earlier post

Answer 7

i think i wrote the question wrong hold on

Answer 8

A bullet is fired horizontally from the top of a building with a muzzle velocity of 500 m/s. A similar bullet dropped from the top of the same building, takes 4 sec to reach the ground. How far forward does the first bullet go before it hits the ground?Which bullet hits the ground first? What is the average speed of the dropped bullett?

Answer 9

thats the right question^^^^

Answer 10

well it's174,7161m around 174m for the similar bullet to hit the ground

Answer 11

can u tell me the answers to all the questions lol

Answer 12

just finished my own physic homework hmm :X

Answer 13

Hmm...do you only seek answers or a tutorial on completing the question?

Answer 14

im not here to get feathered at lol im sorry but yes i do only seek answers

Answer 15

soooooo does anybody have the answers?

Answer 16

\[\bullet1 v0=400m/s^2-9,81m/s^2 \bullet 2 a=9,81 m/s^2 t=4s s=v0t+(0,5)at^2\]

Answer 17

well just some help got to go sleep, I am sure you can figure the rest out yourself :)

Answer 18

i take chemistry lol -_____- f u c k

Answer 19

hahaha I took maritim engineering, 3 months into physics and this crap is easy.

Answer 20

When I dropped out from maritim engineering^^

Answer 21

You might notice that the time take for both bullets to reach the ground is the same.

Applying the motion formula,
\[S_x=u_xt + \frac{ 1 }{ 2 }a_xt^2\], where a=0, u=500, t=4 for first bullet, you get? for the first bullet? How far?

average speed for the bullet:
from the first,
\[S_y=\frac{ 1 }{ 2}(10)(4^2)=80m\]
v=80/4=20

Answer 22

a=-9,81m/s^2 and is the average gravity constant on earth.

Answer 23

a is not= 0

Answer 24

what are all the answers

Answer 25

t=4 is wrong for that formula

Answer 26

nvm ywan sleep sry

Answer 27

yh, sorry about that, though g depends on what the question asks.
t=4 because the only force acting on the bullet is gravity, which acts on the y-axis. Thus the time taken to go through x and y axis is the same.

Answer 28

shadowys knows more than me anyways I thik:) maybe 4is right havent checked

Answer 29

gn

Answer 30

lol so what are the answers

Answer 31

sigh. 2000m, same time and 20ms^-1. Is this something for a test?
@duskwood100 lol I need someone to confirm my answers though.

Answer 32

are you reading the revised question btw

Answer 33

Yes. a dropped bullet take 4s to fall to the ground.

Answer 34

so whats the answer to # 1 #2 amd #3

Answer 35

2000m, same time and 20ms^-1

Answer 36

shankssss

Answer 37

lol you're welcome :)