Question

you are driving around a circular rotary which has a radius of 10 m. at a certain instant of time, your car is travelling at a speed of 4 m/s and slowing down at a rate of 1.20m/s^2. your car's overall acceleration has a magnitude of

Answer 1

@Shadowys can u help him

Answer 2

As shown, the centripetal a at that instant is
\[a=\frac{ 4^2 }{ 10 }= 1.6 ms^{-2}\]
thus the total a is
\[a_{total} = \sqrt{1.2^2 + 1.6^2 }\]
As the slowing a and centripetal a are perpendicular to each other.