Question

@jim_thompson5910 help with trig identities real quick?

Answer 1

cot x sec^4 x=cot x + 2 tan x + tan^3 x

Answer 2

sec^2=1+tan^2

Answer 3

Steps?:O

Answer 4

Do you need help?

Answer 5

Yes

Answer 6

That should help.

Answer 7

Uhh what site is that.. :O

Answer 8

@zordoloom

Answer 9

cot x sec^4 x=cot x + 2 tan x + tan^3 x


cot x sec^4 x=1/tan x + 2 tan x + tan^3 x


cot x sec^4 x=1/tan x + 2 tan^2 x/tan x + tan^3 x


cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^3 x


cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^3 x/1


cot x sec^4 x=(1 + 2 tan^2 x)/tan x + tan^4 x/tan x


cot x sec^4 x=(1 + 2 tan^2 x + tan^4 x)/tan x


cot x sec^4 x=(1 + 2z + z^2)/tan x ... Let z = tan^2 x


cot x sec^4 x=((z+1)^2)/tan x


cot x sec^4 x=((tan^2 x+1)^2)/tan x


cot x sec^4 x=((sec^2)^2)/tan x


cot x sec^4 x=(sec^4 x)/tan x


cot x sec^4 x=cot x sec^4 x

Answer 10

;__; you have different answers?

Answer 11

there are different ways to do this, but they are both valid

Answer 12

notice how I'm only manipulating the right side and I'm changing it into the left side

Answer 13

1/tan x + 2 tan^2 x/tan x + tan^3 x
(1 + 2 tan^2 x)/tan x + tan^3 x
What allowed you to do that?

Answer 14

1/tan x and 2 tan^2 x/tan x are fractions with the same denominator (tan x)

Answer 15

I combined them to get (1 + 2 tan^2 x)/tan x

Answer 16

Thanks a lot @jim_thompson5910 :D

Answer 17

you're welcome