Question

Evaluate the integral.
sec x tan x dx from 0 to pi/4

Answer 1

since

y = sec(x)

turns into

y' = sec(x)*tan(x)

this means that the integral of sec(x)*tan(x) is sec(x) + C

Answer 2

Now evaluate at the endpoints

[sec(pi/4) + C] - [sec(0) + C]

sqrt(2) - 1

So the integral of sec(x)*tan(x) from 0 to pi/4 is sqrt(2) - 1

Answer 3

Is that the antiderivative of sec x tan x?

Answer 4

yes from 0 to pi/4

Answer 5

Thanks.

Answer 6

np