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Mathematics 7 Online
OpenStudy (anonymous):

Two vectors A and B have magnitude A = 3.05 and B = 3.07. Their vector product is AxB= -5.03k + 2.05i . What is the angle between A and B?

OpenStudy (rob1525):

The angle between two vectors is cos (theta)=u*v/mangitude(U)*magnitude(v) then use arccosine to find theta. so, 2.05-5.03/3.50*3.07=-0.31825.. arccosine(-0.31825)=1.89 degrees.

OpenStudy (anonymous):

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