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Chemistry 17 Online
OpenStudy (nali):

how do i use the atomic mass unit (amu) to find the mass of an Ar atom?

OpenStudy (nali):

@Sheng @Preetha can u plz help

OpenStudy (anonymous):

Well, there are many instances that you will use atomic mass. Could you be more specific? I use the atomic mass generally for conversions at the moment. Determining what "1 mol" of something is requires the atomic mass.

OpenStudy (anonymous):

For example: Finding what 1 mol of NaCl2 would be adding the atomic mass of (1) Na and (2) Cl. So you look to your periodic table for the mass of each and add them. (1) Na= 22.989769g (2) Cl= 35.453 x 2 So one mol of NaCl2 is equivalent to 93.895769 grams

OpenStudy (nali):

how to use the amu for finding the mass of an Ar atom ?

OpenStudy (anonymous):

Wouldn't the amu of Ar (39.948) divided by Avogadro's number be the mass of one atom of Ar? I may be wrong...

OpenStudy (aripotta):

no, 39.948 is the mass of 1 mol Ar

OpenStudy (aripotta):

this is just ONE atom, so it will be so much smaller

OpenStudy (aripotta):

first convert one atom to mol 1 atom Ar x (1 mol)/(6.022 x 10^23)

OpenStudy (anonymous):

39.948/6.02214179(30)×1023, right?

OpenStudy (anonymous):

*^23 sorry

OpenStudy (aripotta):

after you convert to mol, you can then convert it to grams using 39.948

OpenStudy (aripotta):

one sec, lemme do the math

OpenStudy (nali):

so how do i use the amu in the end is it like the following Ar atom mass= 39.9g (1.66 x 10^24 kg/ 1 amu )

OpenStudy (nali):

ok i will wait

OpenStudy (aripotta):

1.00 atom Ar = 1.66 x 10^-24

OpenStudy (aripotta):

mol

OpenStudy (aripotta):

1.66 x 10^-24 mol x (39.948g)/(1 mol) = 66.3 x 10^-24g

OpenStudy (aripotta):

i believe...

OpenStudy (nali):

i think that is right but why is 1.66 x 10 ^24 MOL and not kg

OpenStudy (aripotta):

because we had to convert atom to mole, then mole to grams

OpenStudy (nali):

in the back of my book it says 1 amu = 1.66 x 10^24 g

OpenStudy (aripotta):

i'm not sure :/ i learned that 1 mole = 6.022 x 10^24 atoms.

OpenStudy (nali):

yeah that is right

OpenStudy (nali):

but u did not use the amu so what is the point my question is how do i use the amu in this situation

OpenStudy (aripotta):

:/ sorry.

OpenStudy (nali):

it is ok thanku for trying

OpenStudy (anonymous):

This is from the Wikipedia: "In chemistry and physics, the Avogadro constant (symbols: L, NA) is defined as the number of constituent particles (usually atoms or molecules) in a mole of the substance. It is a dimensionless number and has the value 6.02214129(27)×1023 mol−1 So wouldn't the amu of Ar (39.948 g / mol) divided by 6.02214129(27)×1023 mol−1 be the mass of one atom of Ar?

OpenStudy (nali):

no i already know how to use that rule but my teacher gave an example of finding the mass of an Ar atom and he used the amu value not the avogardo's number avagardo's number is supposed to be used when i want know the mass of one mole of Ar atoms not just one Ar atom

OpenStudy (anonymous):

Hmmm... Do you have an answer sheet? If so, what does it say?

OpenStudy (nali):

i have the answer but i wanted to make sure and i think i copied it wrong i have 39.95 g x 1.66 x 10^24 g = 6.63 x 10^ 26

OpenStudy (aripotta):

it would just be 10^24?

OpenStudy (nali):

it is ok i think i have the wrong answer though

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