Question

\[y = \dfrac{10}{1+x^2}\]
\[\text{Find }y'\]

Answer 1

know chain rule ?

Answer 2

Yeah, but how can I apply it?

Answer 3

the question is 10/(1+x^2)
right ?

Answer 4

Wait, let f(x) = 10/x , g(x) = 1+x²

so y' = f'(g(x))g'(x)

Right?

Answer 5

Why are there so many viewers? lol.

Answer 6

y= 10/(1+x^2) ?
if yes,
f(x) = 1/x
g(x) = 1+x^2

Answer 7

10 is constant, can be taken out...

Answer 8

Ok, thanks.

Answer 9

welcome ^_^

Answer 10

y=10/(x^2 + 1)

Answer 11

y=10/(x^2 + 1)