Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

What is the vertex of the parabola y = 5(x + 4)^ 2 + 1 ?

OpenStudy (anonymous):

you have to differentiate and equate to 0. expanding the equation helps to make differentiating easier

OpenStudy (anonymous):

can you show me?

OpenStudy (anonymous):

simplifying: 5x^2 + 40x + 81

OpenStudy (anonymous):

got that?

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

then, differentiate w.r.t x. 10x + 40

OpenStudy (anonymous):

okay...

OpenStudy (anonymous):

equating that to 0 would give you the x-coordinate of the stationary point

OpenStudy (anonymous):

hence x = -4

OpenStudy (anonymous):

put that into your original equation to get the y-coordinate

OpenStudy (anonymous):

so the vertex is (-4,1)

OpenStudy (anonymous):

thanks!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!