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Using Newton's binomial formula. Find the sum of...
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Using Newton's binomial formula. Find the sum of... \[\sum_{k=0}^{n} \left(\begin{matrix}n \\k\end{matrix}\right)\]
this represents one row of pascal's triangle, so the sum is \(2^n\) not sure what "newtons binomial formula" is but i guess you can prove it by induction
actually if you want a snap proof, compute \(2^n\) as \((1+1)^n\) and you will have your result instantly
how do you know it's the first row of pascal's triangle?
it is not the first row, it is the nth row
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i said "one row" which was not precise in any case if you use the binomial formula for \((1+1)^n\) you get your result
i get it. but how did you come to \[2^{n}\] ?
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