The scores on an exam are normally distributed with a mean of 77 and a standard deviation of 10. What percent of the scores are greater than 87? 68% 16% 84% 2.5%
The z-score for an exam score of 87 is 1. A standardised normal distribution table will give you the percentage of exam scores less than 87. Then just subtract this percentage from 100% to get the solution.
so what is the answer
?
Just look up the table here for Z = 1.00 and follow the instructions that I posted: http://faculty.mu.edu.sa/public/uploads/1335623341.239standardnormaltable.pdf
do you have a ti 89?
yeah
i have ti 83
You can do it on you calc by going to apps, look for stats/list, then press f5 and select shade. let me know when you'r there.
Oh and 83 is diff.
This websit should help http://www.ehow.com/how_4523946_find-normal-distribution-ti83-calculator.html
i just wanna know if u can tell me the answer
It looks like 15.86% round to 16 %. You should learn how to do it on your calc its easy.
thanks
no problem
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