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Mathematics 16 Online
OpenStudy (anonymous):

The scores on an exam are normally distributed with a mean of 77 and a standard deviation of 10. What percent of the scores are greater than 87? 68% 16% 84% 2.5%

OpenStudy (kropot72):

The z-score for an exam score of 87 is 1. A standardised normal distribution table will give you the percentage of exam scores less than 87. Then just subtract this percentage from 100% to get the solution.

OpenStudy (anonymous):

so what is the answer

OpenStudy (anonymous):

?

OpenStudy (kropot72):

Just look up the table here for Z = 1.00 and follow the instructions that I posted: http://faculty.mu.edu.sa/public/uploads/1335623341.239standardnormaltable.pdf

OpenStudy (rob1525):

do you have a ti 89?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

i have ti 83

OpenStudy (rob1525):

You can do it on you calc by going to apps, look for stats/list, then press f5 and select shade. let me know when you'r there.

OpenStudy (rob1525):

Oh and 83 is diff.

OpenStudy (rob1525):

This websit should help http://www.ehow.com/how_4523946_find-normal-distribution-ti83-calculator.html

OpenStudy (anonymous):

i just wanna know if u can tell me the answer

OpenStudy (rob1525):

It looks like 15.86% round to 16 %. You should learn how to do it on your calc its easy.

OpenStudy (anonymous):

thanks

OpenStudy (rob1525):

no problem

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