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Chemistry 8 Online
OpenStudy (anonymous):

how would you prepare 300.0 ml of a 0.45 M NaCl solution from solid NaCl and water and from 1.0 M Nacl solution?

OpenStudy (anonymous):

\[M _{1}V _{1}=M _{2}V _{2}\] therefor (V) 1 M NaCl = 300 mL 0.45 M NaCl solve algebraically.

OpenStudy (anonymous):

Can you add equations, attachments, and drawings and explain a little bit more. please

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