Question

Express in lowest terms. 27a^3-1/9a^2-6a+1

Answer 1

9a^2+3a+1/3a_1 B 1/2 c; 3a-1

Answer 2

A;9a^2+3a+1/3a_1 B 1/2 c; 3a-1

Answer 3

@sue101 help

Answer 4

\[27a^3-1/9a^2-6a+1\]

Answer 5

i need help @campbell_st

Answer 6

quick question is it

\[\frac{27a^3 -1}{9a^2 - 6a + 1}\]

Answer 7

yes

Answer 8

ok... that makes it a lot easier

the numerator is the difference of 2 cubes

a^3 - b^3 = (a -b)(a^2 +ab + b^2)

a = 3a b = 1

the denominator is a perfect square can you rewrite both expressions in a factored form..?

Answer 9

c; 3a-1

Answer 10

nope re-write it first, then cancel the common factors...

Answer 11

B 1/2

Answer 12

B ;1/2

Answer 13

ummm unsure... is the denominator double the numerator...?

Answer 14

okey 9a^2+3a+1/3a_1

Answer 15

@campbell_st

Answer 16

ok... how did you get that..?

Answer 17

he denominator is a perfect square can you rewrite both expressions in a factored form..?

Answer 18

ok...so what does the factored form look like..?

Answer 19

i think 9a^2+3a+1/3a_1

Answer 20

@Yahoo!

Answer 21

lol... no the factored form before anthing is cancelled. Thats the skill.... you need to learn...

Answer 22

okey thanks