Solve: x^4+x^3-14x-12=0
I don't think either of you suggestions are roots... just using the factor theorem f(-3) = 81 - 27 + 42 - 12 f(-2) = 16 - 8 + 28 - 12 neither equals zero...
There are two real roots. Refer to the attached plot. { x = -0.863422 }, { x = 2.37565 }
How did you find that? I'm confused on the process so if you could explain that would be really helpful!
I use Mathematica 8 Home Edition for calculating problems on this site. One of the Mathematica functions, NSolve, will provide the numeric solutions shown below.\[\text{NSolve}[x{}^{\wedge}4+x{}^{\wedge}3-14x-12\text{==}0,x] \]{{x->-1.25611-2.06699 I}, {x->-1.25611+2.06699 I},{x -> -0.863422}, {x -> 2.37565}} The two symbolic real solutions are attached as a tiff file. This site's LaTex system appears unable to cope with the solution complexities.
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