Question

Consider the function f(x)=5-3x^2 on the interval [-2,3]. Find the average or mean slope of the function on this interval, i.e.

f(3)-f(-2)/3-(-2)
m=-3

By the Mean Value Theorem, we know there exists a 'c' in the open interval (-2,3) such that f'(c) is equal to this mean slope. For this problem, there is only one 'c' that works. Find it.

I figured out the first part, I can't get the second. Please help?

Answer 1

I would assum that you set the first derivitive function to -3 and then solve for x.

Answer 2

So, -3=-6x now solve for x

Answer 3

how'd you figure that out?

Answer 4

you mean how to solve for x?

Answer 5

just divide -6 from both sides.

Answer 6

oh nevermind

Answer 7

no i meant the derivative but i get it..

Answer 8

okay cool.