Question

Checking my answer:

Answer 1

Determine the solution!

\[\frac{ dy }{ dx } =-\frac{ x }{ y }\]
for y(0) =4
\[y dy = -x dx\]
\[\int\limits_{4}^{y} y dy = - \int\limits_{0}^{x} x dx\]
\[\frac{ y ^{2} }{ 2 } - \frac{ (2^{2}) }{ 2 } = -\frac{ x ^{2} }{ 2 } \]
\[\frac{ y ^{2} }{ 2 } - 2 = -\frac{ x ^{2} }{ 2 }\]
\[\frac{ y ^{2} }{ 2 } = 2 - \frac{ x ^{2} }{ 2 }\]
\[y ^{2} = 4 - x ^{2}\]
\[y = \sqrt{4 -x ^{2}}\]

Answer 2

hbu @kelly226 ???

Answer 3

it looks right 2 mee:)

Answer 4

ok, thank u @kelly226 :)

Answer 5

np :)