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Add them together (as they share a common denominator) and go on from there.
\[\frac{ a }{ b }-\frac{ c }{ b }=\frac{ a-c }{ b }\]
do that then we will do the next step
Whoops, I mean subtract
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6t^3-7/t-1 ?
t+6 again, you can simply combine the numorator, because the demoninator is the same. however, once you have, you can factor the numerator into (t+6) and (t-1). once you have factored, the (t-1) term will cancel out on the top and bottom leaving you with just (t+6)
Subtract 7 from t^2-6t What do you get?
\[\frac{ t^2+6t-7 }{ t-1 }=\frac{ (t-1)(t+7) }{ t-1 }=t+7\]
would it be t+6 or t+7?
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t+7 t^2+6t-7 = (t+7)(t-1) then the t-1 get cancelled
thanks guys!
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